Right now it stands that there are 5-7 pirates...worst case, 7
We've lost 3 innocents. Worst case we started with 9, so there are 6 left.
1 thief.
Best case scenario: 5 Pirates left
Innocents: 11-3.....8 left.
1 thief.
Other Scenario: 6 Pirates left
Innocents: 10-3....7 left
1 thief.
Running the numbers once again:
Worst Case
Pirates: Started: 7 Now: 5
Innocents: Started: 9 Now: 4
Thief: 1
Middle Case
Pirates: Started: 6 Now: 4
Innocents: Started: 10 Now: 5
Thief: 1
Best Case
Pirates: Started: 5 Now: 3
Innocents: Started: 11 Now: 6
Thief: 1
As I stated before, I believe we're looking at a middle/best case senario. We've got 6 known innocents, one living. We're 2 pirates down, and need 1 more for a win. Right now the Cooke has got 2 nights of protection left...IF the Watchman can protect the targetted innocent both these nights, we'll stay where we are. If he can't, we're going to take losses before we can draw more pirate blood.
Our best hope is to find and lynch the only non-protectable Pirate, and that's not going to be an easy task.
Under the worse-case senario, if the watchman chooses wrong one night, only the Magistrate's protection will save an innocent from lynching. Under the middle case, it'd take two wrong picks by the watchman and the thief siding with the pirates or staying neutral in the votes. Best case, even if the watchman fails to pick the pirate's hit accurately we'll stay ahead until Cooke's protection runs out.
So, we've got two things we've gotta do in the next couple nights: A) Find Blackbeard. B) Find the Pirate Target so the watchman can protect him.
I'm still wondering if the Magistrate's jail and slaughter trumps Cooke's protection or not...I'm working the above senarios under the assumption it doesn't, but if it does, it puts us back in the game without dragging this out.