1/2 inch glass vs 3/8 inch glass
- Thread starter terror
- Start date
thanksyou can use 2x4,2x6,4x4 any will help.
the post jacks are just way easier to use
tank alone is quite heavy lol. now i need someone to help me change tanks just want to double confirm, so the size of the plywood under the stand wont matter?
even if i use 1 ft x 1 ft or 6 inch x 6 inch?
that depends on the thickness of the plywood. you should be fine with 6"x6", more than that and you aren't helping much, the weight is only going to transfer out so far.
thanks bgcoop8784, CWO4GUNNER
I currently have another tank of the same size, but its on the 2nd floor of our house.
but the glass of the main tank is thinner, 3/8th inch
here's a picture of the tank with sump
I added plywood underneath, so it would be better to add a whole sheet of plywood, about 4.5 ft x 2.5 ft to distribute the weight , will this help ?
What you have now, as far as shoring (the plywood) is as good as you're going to get, unless you go thicker.
In my job as a boom operator, I'm responsible for loading KC-10 aircraft, among other things. In our cargo loading manual, we have a section on shoring and associated calculations. I shall cut and paste from the shoring section.
The weight of a load resting on shoring is not
spread equally over the entire area of contact
between the shoring and the surface on which
the shoring is resting. In general, shoring will
only increase the area over which a load is
distributed to whatever area is obtained by
extending a plane drawn downward and outward
from the outside line of contact of the load, at
an angle of 45°, until it intersects the surface on
which the shoring rests.
The effect of this geometric
estimation is illustrated in figure 5A-2.
Assume that the shoring is 0.75 inches thick
(one sheet of plywood) and the box is 6 inches
wide by 12 inches long. The area of contact
between the box and plank will be 6 x 12
inches, or 72 square inches. Now extend imaginary
planes downward and outward from the
edges of the bottom of the box at angles of 45°.
Where these imaginary planes intersect the
cargo floor, the area of contact will be 7.5 x
13.5 inches, or 101.3 square inches.
Here is the math to make it work:
Total increased area (for rectangular areas) = (W+2t) x (L+2t) where t = shoring thickness.
For the problem given above, it would look something like this:
The item is 6 x 12 inches and the shoring is .75 inches thick.
Your total area would = (6+1.50) x (12+1.50) which leads to 7.50 x 13.50 which is 101.25 in/sq or, rounded up, 101.3 in/sq vs the 72 in/sq to begin with.
So if you're concerned about the weight bearing capacity of your floor, one way to spread the load would be to either have the legs thick enough to bridge the gap between two floor beams, or build up enough shoring under the stand to do the same. (This is assuming you can't get access to the underside of the floor, as is the case for your 2nd floor.)
thanks for the help bgcoop878, flyingfennec
Currently my plywood is .5 inches only, Would it help if I double the plywood. to increase the thickness thus increasing the area?
will post update here once my tank has been setup
Currently my plywood is .5 inches only, Would it help if I double the plywood. to increase the thickness thus increasing the area?
will post update here once my tank has been setup
